2x^2+2x+1=41

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Solution for 2x^2+2x+1=41 equation:


Simplifying
2x2 + 2x + 1 = 41

Reorder the terms:
1 + 2x + 2x2 = 41

Solving
1 + 2x + 2x2 = 41

Solving for variable 'x'.

Reorder the terms:
1 + -41 + 2x + 2x2 = 41 + -41

Combine like terms: 1 + -41 = -40
-40 + 2x + 2x2 = 41 + -41

Combine like terms: 41 + -41 = 0
-40 + 2x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-20 + x + x2) = 0

Factor a trinomial.
2((-5 + -1x)(4 + -1x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-5 + -1x)' equal to zero and attempt to solve: Simplifying -5 + -1x = 0 Solving -5 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1x = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1x = 0 + 5 -1x = 0 + 5 Combine like terms: 0 + 5 = 5 -1x = 5 Divide each side by '-1'. x = -5 Simplifying x = -5

Subproblem 2

Set the factor '(4 + -1x)' equal to zero and attempt to solve: Simplifying 4 + -1x = 0 Solving 4 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1x = 0 + -4 -1x = 0 + -4 Combine like terms: 0 + -4 = -4 -1x = -4 Divide each side by '-1'. x = 4 Simplifying x = 4

Solution

x = {-5, 4}

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